## 题目描述

A standard playing card deck contains 52 cards, 13 values in each of four suits. The values are named 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King, Ace. The suits are named Clubs, Diamonds, Hearts, Spades. A particular card in the deck can be uniquely identified by its value and suit, typically denoted <value> of <suit>. For example, "9 of Hearts" or "King of Spades". Traditionally a new deck is ordered first alphabetically by suit, then by value in the order given above.

The Big City has many Casinos. In one such casino the dealer is a bit crooked. She has perfected several shuffles; each shuffle rearranges the cards in exactly the same way whenever it is used. A very simple example is the "bottom card" shuffle which removes the bottom card and places it at the top. By using various combinations of these known shuffles, the crooked dealer can arrange to stack the cards in just about any particular order.

You have been retained by the security manager to track this dealer. You are given a list of all the shuffles performed by the dealer, along with visual cues that allow you to determine which shuffle she uses at any particular time. Your job is to predict the order of the cards after each in a sequence of shuffles.

## 输入

Input consists of an integer n <= 100, the number of shuffles that the dealer knows. 52n integers follow. Each consecutive 52 integers will comprise all the integers from 1 to 52 in some order. Within each set of 52 integers, i in position j means that the shuffle moves the ith card in the deck to position j.

Several lines follow; each containing an integer k between 1 and n indicating that you have observed the dealer applying the kth shuffle given in the input.

## 输出

For each test case, assume the dealer starts with a new deck ordered as described above. After all the shuffles had been performed, give the names of the cards in the deck, in the new order. The output of two consecutive cases will be separated by a blank line.

## 样例输入

```
2
2 1 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26
27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 52 51
52 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26
27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 1
1
2
```

## 样例输出

```
3 of Clubs
2 of Clubs
4 of Clubs
5 of Clubs
6 of Clubs
7 of Clubs
8 of Clubs
9 of Clubs
10 of Clubs
Jack of Clubs
Queen of Clubs
King of Clubs
Ace of Clubs
2 of Diamonds
3 of Diamonds
4 of Diamonds
5 of Diamonds
6 of Diamonds
7 of Diamonds
8 of Diamonds
9 of Diamonds
10 of Diamonds
Jack of Diamonds
Queen of Diamonds
King of Diamonds
Ace of Diamonds
2 of Hearts
3 of Hearts
4 of Hearts
5 of Hearts
6 of Hearts
7 of Hearts
8 of Hearts
9 of Hearts
10 of Hearts
Jack of Hearts
Queen of Hearts
King of Hearts
Ace of Hearts
2 of Spades
3 of Spades
4 of Spades
5 of Spades
6 of Spades
7 of Spades
8 of Spades
9 of Spades
10 of Spades
Jack of Spades
Queen of Spades
Ace of Spades
King of Spades
King of Spades
2 of Clubs
4 of Clubs
5 of Clubs
6 of Clubs
7 of Clubs
8 of Clubs
9 of Clubs
10 of Clubs
Jack of Clubs
Queen of Clubs
King of Clubs
Ace of Clubs
2 of Diamonds
3 of Diamonds
4 of Diamonds
5 of Diamonds
6 of Diamonds
7 of Diamonds
8 of Diamonds
9 of Diamonds
10 of Diamonds
Jack of Diamonds
Queen of Diamonds
King of Diamonds
Ace of Diamonds
2 of Hearts
3 of Hearts
4 of Hearts
5 of Hearts
6 of Hearts
7 of Hearts
8 of Hearts
9 of Hearts
10 of Hearts
Jack of Hearts
Queen of Hearts
King of Hearts
Ace of Hearts
2 of Spades
3 of Spades
4 of Spades
5 of Spades
6 of Spades
7 of Spades
8 of Spades
9 of Spades
10 of Spades
Jack of Spades
Queen of Spades
Ace of Spades
3 of Clubs
```

## 参考代码

```
#include <stdio.h>
int d[101][53];
int deck[53], newdeck[53];
char *suit[] = {"Clubs", "Diamonds", "Hearts", "Spades"};
char *value[] = {"2","3","4","5","6","7","8","9","10","Jack","Queen",
"King","Ace"};
int i,j,k,deal,deals;
int main()
{
scanf("%d",&deals);
for (i=1;i<=deals;i++) for (j=1;j<=52;j++) scanf("%d",&d[i][j]);
for (i=1;i<=52;i++) deck[i] = i;
while (1 == scanf("%d",&deal))
{
for (i=1;i<=52;i++) newdeck[i] = deck[d[deal][i]];
for (i=1;i<=52;i++) deck[i] = newdeck[i];
for (i=1;i<=52;i++)
{
printf("%s of %sn",value[(deck[i]-1)%13],suit[(deck[i]-1)/13]);
}
printf("n");
}
}
```

## 解析

暂无