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1645: Beautiful Number

发表于 2017-10-06   |   分类于 HUSTOJ   |   阅读次数 1,433

题目描述

Mike is very lucky, as he has two beautiful numbers, 3 and 5. But he is so greedy that he wants infinite beautiful numbers. So he declares that any positive number which is dividable by 3 or 5 is beautiful number. Given you an integer N (1 <= N <= 100000), could you please tell mike the Nth beautiful number?

输入

The input consists of one or more test cases. For each test case, there is a single line containing an integer N.

输出

For each test case in the input, output the result on a line by itself.

样例输入

1
2
3
4

样例输出

3
5
6
9

参考代码

#include <stdio.h>
int main() 
{
    int intInput;
    int intQuo;
    int intAri;
    int intNumber;
    int a[7]={12,0,2,3,6,7,9};
    int intFirst;
    while(scanf("%d",&intInput)!=EOF) 
    {
        intFirst=0;
        intQuo=intInput/7;
        intAri=intInput%7;
        if(0==intAri) 
        {
            intFirst=3+15*(intQuo-1);
        } else 
        {
            intFirst=3+15*intQuo;
        }
        intNumber=intFirst+a[intAri];
        printf("%dn",intNumber);
 }
 return 0;
}

解析

暂无

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若是凉夜已成梦

若是凉夜已成梦

青春里 总有些事情要努力去做 总有些梦想要拼命去追。

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