题目描述
Given an positive integer A (1 <= A <= 100), output the lowest bit of A.
For example, given A = 26, we can write A in binary form as 11010, so the lowest bit of A is 10, so the output should be 2.
Another example goes like this: given A = 88, we can write A in binary form as 1011000, so the lowest bit of A is 1000, so the output should be 8.
输入
Each line of input contains only an integer A (1 <= A <= 100). A line containing "0" indicates the end of input, and this line is not a part of the input data.
输出
For each A in the input, output a line containing only its lowest bit.
样例输入
26
88
0
样例输出
2
8
参考代码
#include<stdio.h>
int main()
{
int a;
while(scanf("%d",&a)==1&&a!=0)
{
int b[7];
int i=0;
do
{
if(a/2==0)break;
b[i++]=a%2;
a=a/2;
}
while(a/2);
b[i]=a%2;
int j=0;
for (j;j<=i;j++)
{
if(b[j]!=0)break;
}
int sum=1;
for (i=0;i<j;i++)
{
sum*=2;
}
printf("%dn",sum);
}
return 0;
}
解析
暂无
