若是凉夜已成梦

青春里 总有些事情要努力去做 总有些梦想要拼命去追。


  • 运维

  • 前端

  • 编程

  • 随笔

  • hust-oj

2375: aaah

发表于 2017-10-06   |   分类于 HUSTOJ   |   阅读次数 1,179

题目描述

Jon Marius shouted too much at the recent Justin Bieber concert, and now needs to go to the doctor because of his sore throat. The doctor’s instructions are to say “aaah”. Unfortunately, the doctors sometimes need Jon Marius to say “aaah” for a while, which Jon Marius has never been good at. Each doctor requires a certain level of “aah” – some require “aaaaaah”, while others can actually diagnose his throat with just a “h”. (They often diagnose wrongly, but that is beyond the scope of this problem.) Since Jon Marius does not want to go to a doctor and have his time wasted, he wants to compare how long he manages to hold the “aaah” with the doctor’s requirements. (After all, who wants to be all like “aaah” when the doctor wants you to go “aaaaaah”?)
Each day Jon Marius calls up a different doctor and asks them how long his “aaah” has to be. Find out if Jon Marius would waste his time going to the given doctor.

输入

The input consists of two lines. The first line is the “aaah” Jon Marius is able to say that day. The second line is the “aah” the doctor wants to hear. Only lowercase ’a’ and ’h’ will be used in the input, and each line will contain between 0  and 999  ’a’s, inclusive, followed by a single ’h’.

输出

Output “go” if Jon Marius can go to that doctor, and output “no” otherwise.

样例输入

aaah
aaaaah

样例输出

no

参考代码

#include<stdio.h>
#include<string.h>
int main() 
{
    char s[1000],a[1000];
    gets(a);
    gets(s);
    printf(strlen(a)<strlen(s)?"no":"go");
    return 0;
}

解析

暂无

hustoj

发表评论 取消回复

邮箱地址不会被公开。 必填项已用*标注

*
*


hoxis wechat
著作权归作者所有
站点更新说明
  • 文章目录
  • 站点概览
若是凉夜已成梦

若是凉夜已成梦

青春里 总有些事情要努力去做 总有些梦想要拼命去追。

1904 日志
6 分类
12 标签
RSS
weibo github twitter facebook

友情链接

Dreams孤独患者 原站点 Skip
© 2017 若是凉夜已成梦
Powered by WordPress | 已运行
Theme By NexT.Mist