题目描述
Given an integer n,your task is to calculate 1+2+…+N;
输入
The first line of input contains an integer T, indicating the number of test cases (T<=20)
The each test case contains a single positive integer N(N<=2^32).
输出
For each input you should output the sum of 1+2+…+N in one line.(The result must less than 2^63)
样例输入
2
10
1
样例输出
55
1
参考代码
#include<stdio.h>
int main()
{
int m,i;
unsigned long long n;
scanf("%d",&m);
for (i=0;i<m;i++)
{
scanf("%lld",&n);
n=(n*(n+1))/2;
printf("%lldn",n);
}
return 0;
}
解析
暂无